cos^4x+sin^2x-sin^4x=1

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Solution for cos^4x+sin^2x-sin^4x=1 equation: 


Simplifying
cos4x + sin2x + -1sin4x = 1

Solving
cos4x + in2sx + -1in4sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2sx' to each side of the equation.
cos4x + in2sx + -1in2sx + -1in4sx = 1 + -1in2sx

Combine like terms: in2sx + -1in2sx = 0
cos4x + 0 + -1in4sx = 1 + -1in2sx
cos4x + -1in4sx = 1 + -1in2sx

Add 'in4sx' to each side of the equation.
cos4x + -1in4sx + in4sx = 1 + -1in2sx + in4sx

Combine like terms: -1in4sx + in4sx = 0
cos4x + 0 = 1 + -1in2sx + in4sx
cos4x = 1 + -1in2sx + in4sx

Divide each side by 'os4x'.
c = o-1s-4x-1 + -1in2o-1s-3 + in4o-1s-3

Simplifying
c = o-1s-4x-1 + -1in2o-1s-3 + in4o-1s-3

Reorder the terms:
c = -1in2o-1s-3 + in4o-1s-3 + o-1s-4x-1

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